16  Wave Behaviour

16.1 Syllabus inquiry question

  • How do waves interact with boundaries and with each other?
Feynman Insight

From The Feynman Lectures on Physics, Vol I, Chapter 27:

Wave behaviour is governed by superposition. Reflection, refraction, and interference are all consequences of adding disturbances.

16.2 Learning Objectives

  • Describe reflection and refraction of waves.
  • Explain superposition and interference.
  • Identify standing waves, nodes, and antinodes.
  • Apply simple rules for wave boundary behaviour.

16.3 Content

16.3.1 Reflection of Waves

When a wave reaches a boundary, some or all of it reflects back.

Fixed boundary (hard reflection): - Wave inverts upon reflection - Crest becomes trough, trough becomes crest - Examples: String fixed to a wall, sound reflecting from a wall

Free boundary (soft reflection): - Wave reflects without inversion - Crest remains crest, trough remains trough - Examples: String with a loose end, open pipe end

16.3.2 Interactive: Wave Reflection

A pulse approaching a boundary:

16.3.3 Refraction of Waves

Refraction occurs when a wave changes speed as it enters a new medium. The frequency stays constant, but wavelength changes.

Key points: - Wave bends toward the normal when slowing down - Wave bends away from the normal when speeding up - Frequency is preserved across the boundary

16.3.4 Superposition Principle

When two or more waves overlap, the principle of superposition states:

The resultant displacement at any point is the sum of the individual displacements.

\[y_{total} = y_1 + y_2 + y_3 + ...\]

This leads to interference patterns.

16.3.5 Interactive: Constructive Interference

Two waves in phase combine to produce a larger amplitude:

Constructive interference: Waves in phase (\(\Delta\phi = 0\)) → amplitudes add → larger resultant.

16.3.6 Interactive: Destructive Interference

Two waves out of phase (180°) combine to cancel:

Destructive interference: Waves 180° out of phase (\(\Delta\phi = \pi\)) → amplitudes subtract → smaller or zero resultant.

16.3.7 Types of Interference

Condition Phase Difference Path Difference Result
Constructive \(0, 2\pi, 4\pi, ...\) \(0, \lambda, 2\lambda, ...\) Maximum amplitude
Destructive \(\pi, 3\pi, 5\pi, ...\) \(\lambda/2, 3\lambda/2, ...\) Minimum amplitude

16.3.8 Standing Waves

Standing waves form when two identical waves travel in opposite directions and interfere.

Key features: - Nodes: Points of zero displacement (destructive interference) - Antinodes: Points of maximum displacement (constructive interference) - The pattern appears stationary, but energy oscillates between nodes

Node Spacing

The distance between adjacent nodes = \(\lambda/2\)

The distance between adjacent antinodes = \(\lambda/2\)

16.3.9 Interactive: Standing Wave Pattern

16.3.10 Standing Waves on Strings

For a string fixed at both ends, only certain wavelengths produce standing waves:

Harmonic Loops Wavelength Frequency
1st (fundamental) 1 \(\lambda_1 = 2L\) \(f_1\)
2nd 2 \(\lambda_2 = L\) \(f_2 = 2f_1\)
3rd 3 \(\lambda_3 = 2L/3\) \(f_3 = 3f_1\)
nth n \(\lambda_n = 2L/n\) \(f_n = nf_1\)

16.4 Worked Examples

16.4.1 Example 1: Reflection at a fixed end

A pulse travels along a rope and reflects from a fixed end.

Solution:

  1. At a fixed boundary, the pulse inverts upon reflection

  2. A crest becomes a trough; a trough becomes a crest

  3. The reflected pulse travels back with the same speed but inverted shape

16.4.2 Example 2: Constructive interference

Two waves of equal amplitude (\(A = 0.5\) m) overlap in phase.

Solution:

  1. Apply superposition: \(A_{total} = A_1 + A_2\)

  2. Substitute: \(A_{total} = 0.5 + 0.5 = 1.0\) m

  3. The amplitude doubles—this is constructive interference

16.4.3 Example 3: Standing wave wavelength

A string of length 1.2 m forms a standing wave with two complete loops.

Solution:

  1. Two loops (or antinodes) corresponds to one full wavelength

  2. Therefore: \(\lambda = L = 1.2\) m

  3. Node spacing: \(\lambda/2 = 0.60\) m

16.4.4 Example 4: Harmonic frequencies

A guitar string vibrates at fundamental frequency 220 Hz. Find the 2nd and 3rd harmonic frequencies.

Solution:

  1. The nth harmonic frequency: \(f_n = nf_1\)

  2. 2nd harmonic: \(f_2 = 2 \times 220 = 440\) Hz

  3. 3rd harmonic: \(f_3 = 3 \times 220 = 660\) Hz

16.5 Common Misconceptions

Common Misconceptions
  • Misconception: Refraction changes frequency. Correction: Frequency stays constant; only wavelength and speed change.

  • Misconception: Destructive interference destroys energy. Correction: Energy redistributes; total energy is conserved. Where destructive interference occurs, energy appears elsewhere as constructive interference.

  • Misconception: Standing waves travel back and forth. Correction: The pattern is stationary; nodes never move. Energy oscillates between potential and kinetic forms.

  • Misconception: Interference only happens with sound or light. Correction: All waves—water, string, electromagnetic—exhibit interference when they overlap.

16.6 Practice Questions

16.6.1 Easy (2 marks)

A wave reflects from a fixed boundary. Describe what happens to the reflected pulse.

  • Pulse inverts (crest ↔︎ trough) (1)
  • Direction reverses (1)

Answer: The pulse inverts (crest becomes trough) and travels back in the opposite direction.

16.6.2 Medium (4 marks)

Two waves of amplitude 0.30 m overlap with a phase difference of 180°. Find the resulting amplitude.

  • Recognise 180° = completely out of phase (1)
  • Apply subtraction: \(A = |0.30 - 0.30|\) (2)
  • Correct answer: \(A = 0\) (1)

Answer: Zero amplitude (complete destructive interference)

16.6.3 Hard (5 marks)

A 0.80 m string has three complete loops in a standing wave. Find the wavelength and the node spacing.

  • Three loops = 1.5 wavelengths in string length (2)
  • \(\lambda = L/(1.5) = 0.80/1.5 = 0.533\) m (2)
  • Node spacing = \(\lambda/2 = 0.27\) m (1)

Answer: Wavelength = 0.53 m, Node spacing = 0.27 m

16.7 Multiple Choice Questions

Test your understanding with these interactive questions:

16.8 Summary

Key Takeaways
  • Reflection at a fixed boundary inverts the wave; at a free boundary it doesn’t
  • Refraction changes wavelength and speed but not frequency
  • Superposition: resultant displacement = sum of individual displacements
  • Constructive interference (in phase) increases amplitude
  • Destructive interference (out of phase) decreases amplitude
  • Standing waves have stationary nodes and antinodes

16.9 Self-Assessment

Check your understanding:

After studying this section, you should be able to: